document.write( "Question 698107: Given that x and y are real numbers satisfying the equations 3x−2y=21 and 7x+3y=95, what is the value of x+y? \n" ); document.write( "
Algebra.Com's Answer #430835 by sofiyac(983)\"\" \"About 
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STEP 1: \r
\n" ); document.write( "\n" ); document.write( "Multiply each equation by a number that will create
\n" ); document.write( " opposite coefficients for x.
\n" ); document.write( "In this case we will multiply first equation
\n" ); document.write( " by -7 and the second equation by 3;
\n" ); document.write( "After multiplying we have the following system: \r
\n" ); document.write( "\n" ); document.write( "-21x+14y=-147
\n" ); document.write( "21x+9y-285\r
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\n" ); document.write( "\n" ); document.write( "STEP 2: add the two equations together to eliminate x from the system.
\n" ); document.write( "23y=138\r
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\n" ); document.write( "\n" ); document.write( "STEP 3: find y \r
\n" ); document.write( "\n" ); document.write( "y=6\r
\n" ); document.write( "\n" ); document.write( "STEP 4: substitute the value for y into the original equation to solve for x.\r
\n" ); document.write( "\n" ); document.write( "3x-2(6)=21
\n" ); document.write( "3x=33
\n" ); document.write( "x=11\r
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\n" ); document.write( "\n" ); document.write( "add x+y and you get 11+6=17\r
\n" ); document.write( "\n" ); document.write( "Sorry about that, must have made a mistake somewhere!!!! :)
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