document.write( "Question 62388: 3. -9(x-3)^2=-7\r
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document.write( "I got as far as x-3=rs 7/3 no radical sign.\r
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document.write( "Now I then do x=3/5 rs over the three and times it by 9/5. Do I multiply the 7 times the nine or or just leave it as 9 plus or negative over 7/3. \n" );
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Algebra.Com's Answer #43083 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! You were almost done, you forgot that when you take the square root of both sides of an equation it's +/- the other side. All you would need, then is to add 3 to both sides. \n" ); document.write( "3. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " \n" ); document.write( " |