document.write( "Question 62388: 3. -9(x-3)^2=-7\r
\n" ); document.write( "\n" ); document.write( "I got as far as x-3=rs 7/3 no radical sign.\r
\n" ); document.write( "\n" ); document.write( "Now I then do x=3/5 rs over the three and times it by 9/5. Do I multiply the 7 times the nine or or just leave it as 9 plus or negative over 7/3.
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Algebra.Com's Answer #43083 by funmath(2933)\"\" \"About 
You can put this solution on YOUR website!
You were almost done, you forgot that when you take the square root of both sides of an equation it's +/- the other side. All you would need, then is to add 3 to both sides.
\n" ); document.write( "3. \"-9%28x-3%29%5E2=-7\"
\n" ); document.write( "\"-9%28x-3%29%5E2%2F-9=-7%2F-9\"
\n" ); document.write( "\"%28x-3%29%5E2=7%2F9\"
\n" ); document.write( "\"sqrt%28%28x-3%29%5E2%29=%2B-sqrt%287%2F9%29\"
\n" ); document.write( "\"x-3=%2B-sqrt%287%29%2F3\"
\n" ); document.write( "\"x-3%2B3=3%2B-sqrt%287%29%2F3\"
\n" ); document.write( "\"x=3-sqrt%287%29%2F3\" and \"x=3%2Bsqrt%287%29%2F3\" <---this is fine
\n" ); document.write( "\"x=%289-sqrt%287%29%29%2F3\" and \"x=%289%2Bsqrt%287%29%29%2F3\" is also fine.
\n" ); document.write( "Happy Calculating!!!
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