document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=697474>Question 697474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the surface area of a solid prism of length 15cm, the cross-section of the prism is a semi-circle of radius 4cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430825 by </B><A HREF=/tutors/aboutme.mpl?userid=Simnepi><B>Simnepi(216)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Simnepi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Simnepi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the area of the cylinder's ends are given by <BR>\n" );
document.write( "Area = pi X radius^2<BR>\n" );
document.write( "A = pi X 4^2 = 50.265cm^2 to 3 decimal places<BR>\n" );
document.write( "Therefore their area is 50.265 cm^2 each, which totals 100.53 cm^2<BR>\n" );
document.write( "The area of the curved surface of the cylinder is found by finding the circumference of the one end of the cylinder and multiplying this by the length (imagine rolling up a piece of paper to make a hollow tube)<BR>\n" );
document.write( "Circumference = pi X diameter<BR>\n" );
document.write( "C = pi X 8 = 25.133 to 3 decimal places<BR>\n" );
document.write( "So the curved area is<BR>\n" );
document.write( "Area = 25.133 X 15 = 376.995 cm^2<BR>\n" );
document.write( "The total surface area is therefore<BR>\n" );
document.write( "100.53 + 376.995 = 477.525 cm^2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );