document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62388>Question 62388</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3.  -9(x-3)^2=-7\r<BR>\n" );
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document.write( "I got as far as x-3=rs 7/3 no radical sign.\r<BR>\n" );
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document.write( "Now I then do x=3/5 rs over the three and times it by 9/5. Do I multiply the 7 times the nine or  or just leave it as 9 plus or negative over 7/3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43082 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -9(x-3)^2=-7 <BR>\n" );
document.write( "(x-3)^2=7/9<BR>\n" );
document.write( "Take the sqrt of both sides to get:<BR>\n" );
document.write( "x-3=sqrt7/3<BR>\n" );
document.write( "x=(sqrt7)/3 + 3<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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