document.write( "Question 698535: ABCD IS A RHOMBUS, AC=10CM AND AB=12CM. FIND BD.\r
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Algebra.Com's Answer #430785 by neatmath(302)\"\" \"About 
You can put this solution on YOUR website!

A rhombus is a parallelogram with 4 equal sides.
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\n" ); document.write( "\n" ); document.write( "So if you know the length of one side, you know the length of all 4 sides.
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\n" ); document.write( "\n" ); document.write( "Also, the diagonals of a rhombus always bisect each other,
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\n" ); document.write( "\n" ); document.write( "and they are always perpendicular to each other.
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\n" ); document.write( "\n" ); document.write( "So let's draw the diagonals, where M is the intersection of the diagonals,
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\n" ); document.write( "\n" ); document.write( "and notice we will form a right triangle AMD.
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\n" ); document.write( "\n" ); document.write( "Using this, we can find DM, and we know that \"DM=%281%2F2%29%2ADB\"
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\n" ); document.write( "\n" ); document.write( "We can use the Pythagorean Theorem at this point.
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\n" ); document.write( "\n" ); document.write( "\"%28AM%29%5E2%2B%28DM%29%5E2=%28AD%29%5E2\"
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\n" ); document.write( "\n" ); document.write( "\"5%5E2%2B%28DM%29%5E2=12%5E2\"
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\n" ); document.write( "\n" ); document.write( "\"25%2B%28DM%29%5E2=144\"
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\n" ); document.write( "\n" ); document.write( "\"%28DM%29%5E2=119\"
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\n" ); document.write( "\n" ); document.write( "\"DM=sqrt%28119%29\"
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\n" ); document.write( "\n" ); document.write( "Since \"DM=%281%2F2%29%2ADB\", we can see that:
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28119%29=%281%2F2%29%2ADB\"
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%28119%29=DB\"
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\n" ); document.write( "\n" ); document.write( "So diagonal \"DB=2%2Asqrt%28119%29\" cm or approximately 21.8 cm.
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\n" ); document.write( "\n" ); document.write( "I hope this helps! Keep practicing! :)
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