document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=698535>Question 698535</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ABCD IS A RHOMBUS, AC=10CM AND AB=12CM. FIND BD.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430784 by </B><A HREF=/tutors/aboutme.mpl?userid=Simnepi><B>Simnepi(216)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Simnepi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Simnepi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since the angles of a rhombus bisect each other and are perpendicular and meet at E you can make right angled triangle ABE <BR>\n" );
document.write( "AB=12cm, AE=5cm and BE is half BD<BR>\n" );
document.write( "Using Pythagoras<BR>\n" );
document.write( "AE^2 + BE^2 = AB^2<BR>\n" );
document.write( "5^2 + BE^2 = 12^2<BR>\n" );
document.write( "25 + BE^2 = 144<BR>\n" );
document.write( "BE^2 = 144 - 25<BR>\n" );
document.write( "BE^2 = 119<BR>\n" );
document.write( "BE = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28119%29 ALIGN=MIDDLE  ALT=\"sqrt%28119%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "BE = 10.9cm (to 1 decimal place)<BR>\n" );
document.write( "BD = 21.8cm </SPAN>\n" );
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