document.write( "Question 62384: twice the lesser of two consecutive intergers is 12 less than 3 times the greater interger find the lesser interger
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Algebra.Com's Answer #43077 by funmath(2933)\"\" \"About 
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twice the lesser of two consecutive intergers is 12 less than 3 times the greater interger find the lesser interger
\n" ); document.write( "Let the first integer be: x
\n" ); document.write( "Then the second integer is:x+1
\n" ); document.write( "Twice the lesser is:2x
\n" ); document.write( "12 less than 3 times the greater is: 3(x+1)-12
\n" ); document.write( "is means:=
\n" ); document.write( "2x=3(x+1)-12
\n" ); document.write( "2x=3x+3-12
\n" ); document.write( "2x=3x-9
\n" ); document.write( "2x-3x=-3x+3x-9
\n" ); document.write( "-x=-9
\n" ); document.write( "-x/-1=-9/-1
\n" ); document.write( "x=9
\n" ); document.write( "The lesser integer is 9
\n" ); document.write( "Sanity check:
\n" ); document.write( "If the smaller integer is 9, then the greater integer is 10. Is twice the smaller integer equal to 3 times the greater integer less 12?
\n" ); document.write( "2(9)=3(10)-12
\n" ); document.write( "18=30-12
\n" ); document.write( "18=18 Looks good.
\n" ); document.write( "Happy Calculating!!! \n" ); document.write( "
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