document.write( "Question 698341: the distribution of annual incomes of a sample of college graduates is normally distributed with a mean of $52000 and a standard deviation of $1000. About 68 percent of the incomes lie between what two income levels? \n" ); document.write( "

Algebra.Com's Answer #430769 by Positive_EV(69) $\"\"$ $\"About$

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There is a useful rule in statistics called the 68-95-99.7 Rule. It says that, for normally distributed data, 68% of values lie between -1 and 1 standard deviation from the mean, 95% lie between -2 and 2 standard deviations from the mean, and 99.7% lie between -3 and 3 standard deviations from the mean.
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\n" ); document.write( "\n" ); document.write( "Using this rule, 68% of incomes lie between the mean +/- 1 standard deviation. Here, this is $52,000 +/- $1,000 = $51,000-$53,000. \n" ); document.write( "

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