document.write( "Question 698308: please help me to solve this age problem:\r
\n" ); document.write( "\n" ); document.write( "Alice is 8/3 as old as her daughter in 4 years. Alice will be 9/4 as old as her daughter find their ages?
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Algebra.Com's Answer #430752 by KMST(5328)\"\" \"About 
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The problem should be
\n" ); document.write( "“Alice is 8/3 as old as her daughter.
\n" ); document.write( "In 4 years, Alice will be 9/4 as old as her daughter.
\n" ); document.write( "Find their ages”
\n" ); document.write( "\"x\" = Alice's age
\n" ); document.write( "\"y\" = the daughter's age
\n" ); document.write( "\"x=%288%2F3%29y\" because Alice is 8/3 as old as her daughter.
\n" ); document.write( "\"x=%288%2F3%29y\" --> \"3x=8y\" --> \"3x-8y=0\"
\n" ); document.write( "In 4 years, Alice will be \"x%2B4\",
\n" ); document.write( "her daughter will be \"y%2B4\",
\n" ); document.write( "and their ages will be related by the equation
\n" ); document.write( "\"x%2B4=%289%2F4%29%28y%2B4%29\" --> \"4%28x%2B4%29=9%28y%2B4%29\" --> \"4x%2B16=9y%2B36\" --> \"4x-9y=36-16\" --> \"4x-9y=20\"
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\n" ); document.write( "We get the system
\n" ); document.write( "\"system%283x-8y=0%2C4x-9y=20%29\"
\n" ); document.write( "Multiplying the first equation times \"%28-4%29\" and the second times \"3\" we get
\n" ); document.write( "\"system%28-12x%2B32y=0%2C12x-27y=60%29\" , and adding both equations we get
\n" ); document.write( "\"5y=60\" --> \"y=60%2F5\" --> \"highlight%28y=12%29\"
\n" ); document.write( "Substituting into \"3x=8y\" we get
\n" ); document.write( "\"3x=8%2A12\" --> \"3x=96\" --> \"x=96%2F3\" --> \"highlight%28x=32%29\"
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