document.write( "Question 698364: X^(2/3)-6x^(1/3)+5 \n" ); document.write( "
Algebra.Com's Answer #430751 by KMST(5328)\"\" \"About 
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You probably meant x^(2/3)-6x^(1/3)+5=0
\n" ); document.write( "With the change of variable y=x^(1/3) --> x^(2/3)=[x^(1/3)]^2=y^2 ,
\n" ); document.write( "the equation turns into the quadratic equation
\n" ); document.write( "\"y%5E2-6y%2B5=0\" with solutions \"y=1\" and \"y=5\"
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\n" ); document.write( "Going back to \"x\" ,
\n" ); document.write( "y=x^(1/3) <--> \"y%5E3=x\" , so
\n" ); document.write( "\"y=1\" --> \"y%5E3=x=1%5E3=1\" --> \"highlight%28x=1%29\"
\n" ); document.write( "\"y=5\" --> \"y%5E3=x=5%5E3=125\" --> \"highlight%28x=125%29\"
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