document.write( "Question 698510: How do I solve the following logarithm for x?\r
\n" ); document.write( "\n" ); document.write( "The base of the following logs is 2.\r
\n" ); document.write( "\n" ); document.write( "log(x-1) - log(x+3) = log(1/x)
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Algebra.Com's Answer #430742 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"log%28x-1%29+-+log%28x%2B3%29+=+log%281%2Fx%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%28x-1%29%2F%28x%2B3%29%29+=+log%281%2Fx%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%2F%28x%2B3%29+=+1%2Fx\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%29x+=+1%28x%2B3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x+=+x%2B3\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-x-3=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x-3=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-2%29+%2B-+sqrt%28%28-2%29%5E2-4%2A1%2A%28-3%29+%29%29%2F%282%2A1%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%284%2B12+%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%2816+%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+4%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B+4%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+6%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3+\"\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%282-+4%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+-2%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=-1+\"\r
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