document.write( "Question 698510: How do I solve the following logarithm for x?\r
\n" ); document.write( "\n" ); document.write( "The base of the following logs is 2.\r
\n" ); document.write( "\n" ); document.write( "log(x-1) - log(x+3) = log(1/x)
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Algebra.Com's Answer #430741 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The base of the following logs is 2.
\n" ); document.write( "log2(x-1) - log2(x+3) = log2(1/x)
\n" ); document.write( "-----\r
\n" ); document.write( "\n" ); document.write( "log2[(x-1)/(x+3)] = log2(1/x)
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\n" ); document.write( "Take the antilog of both sides:
\n" ); document.write( "(x-1)/(x+3) = 1/x
\n" ); document.write( "----
\n" ); document.write( "Cross-multiply:
\n" ); document.write( "x^2-x = x+3
\n" ); document.write( "------
\n" ); document.write( "x^2 -2x - 3 = 0
\n" ); document.write( "---
\n" ); document.write( "Factor:
\n" ); document.write( "(x-3)(x+1) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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