document.write( "Question 698510: How do I solve the following logarithm for x?\r
\n" );
document.write( "\n" );
document.write( "The base of the following logs is 2.\r
\n" );
document.write( "\n" );
document.write( "log(x-1) - log(x+3) = log(1/x) \n" );
document.write( "
Algebra.Com's Answer #430741 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The base of the following logs is 2. \n" ); document.write( "log2(x-1) - log2(x+3) = log2(1/x) \n" ); document.write( "-----\r \n" ); document.write( "\n" ); document.write( "log2[(x-1)/(x+3)] = log2(1/x) \n" ); document.write( "------ \n" ); document.write( "Take the antilog of both sides: \n" ); document.write( "(x-1)/(x+3) = 1/x \n" ); document.write( "---- \n" ); document.write( "Cross-multiply: \n" ); document.write( "x^2-x = x+3 \n" ); document.write( "------ \n" ); document.write( "x^2 -2x - 3 = 0 \n" ); document.write( "--- \n" ); document.write( "Factor: \n" ); document.write( "(x-3)(x+1) = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "x = 3 \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( " |