document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=698508>Question 698508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How can I write the following logarithmic equation as a single logarithm simplified?\r<BR>\n" );
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document.write( "For the following equation, the base of the logs is 3.\r<BR>\n" );
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document.write( "2*log5  +  log4  -  (log15  +  log20) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430740 by </B><A HREF=/tutors/aboutme.mpl?userid=Positive_EV><B>Positive_EV(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Positive_EV><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Positive_EV><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430740\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the property that log(a*b) = log(a) + log(b) for any base of logarithm:\r<BR>\n" );
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document.write( "2*log5 + log4 - (log15 + log20) = 2*log5 + log4 - (log3 + log5 + log4 + log5)<BR>\n" );
document.write( "= 2*log5 - 2*log5 + log4 - log4 - log3<BR>\n" );
document.write( "= -log3\r<BR>\n" );
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document.write( "Since the base of the logarithm is 3, we evaluate -(log base 3 of 3) = -1. </SPAN>\n" );
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