document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=698407>Question 698407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equation for the graph with vertex (-6,3) and focus (-6,0.25).\r<BR>\n" );
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document.write( "a. (x+6)^2=11(y-3)      c. (y-3)^2=-11(x+6)\r<BR>\n" );
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document.write( "b. (x+6)^2=-11(y-3)     d. (y+6)^2=-11(x-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430688 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430688\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write the equation for the graph with vertex (-6,3) and focus (-6,0.25). <BR>\n" );
document.write( "This is a parabola that opens downwards.<BR>\n" );
document.write( "Its standard form of equation: (x-h)^2=-4p(y-k), (h,k)=coordinates of vertex<BR>\n" );
document.write( "Given vertex: (-6,3)<BR>\n" );
document.write( "Axis of symmetry: x=-6<BR>\n" );
document.write( "given focus:(-6,0.25)<BR>\n" );
document.write( "p=3-.25=2.75 (distance from vertex to focus on the axis of symmetry)<BR>\n" );
document.write( "4p=11<BR>\n" );
document.write( "Equation:  (x+6)^2=-11(y-3) (ans. d) </SPAN>\n" );
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