document.write( "Question 698422: what is the slope-intercept form of (2,0); perpendicular to 5y=-x+2 for the line that passes through the given point?
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Algebra.Com's Answer #430659 by josmiceli(19441)\"\" \"About 
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\"+5y+=+x+%2B+2+\"
\n" ); document.write( "\"+y+=+%281%2F5%29%2Ax+%2B+2%2F5+\"
\n" ); document.write( "Any line perpendicular to this line will have slope = \"+-1%2Fm+\"
\n" ); document.write( "where \"+m+\" is the slope of the given line. In this case, \"+m+=+1%2F5+\"
\n" ); document.write( "\"+-1%2Fm+=+-5+\"
\n" ); document.write( "Now given ( 2,0 ) and \"+m+=+-5+\",
\n" ); document.write( "I can write the general point-slope formula:
\n" ); document.write( "\"+%28+y+-+0+%29+%2F+%28+x+-+2+%29+=+-5+\"
\n" ); document.write( "\"+y+=+-5%2A%28+x+-+2+%29+\"
\n" ); document.write( "\"+y+=+-5x+%2B+10+\" answer
\n" ); document.write( "check:
\n" ); document.write( "Does it go through (2,0) ?
\n" ); document.write( "\"+0+=+-5%2A2+%2B+10+\"
\n" ); document.write( "\"+0+=+-10+%2B+10+\"
\n" ); document.write( "\"+0+=+0+\"
\n" ); document.write( "OK
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