document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=698414>Question 698414</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are 13 animals in the barn.some are chicken some are pigs. there are 40 legs in all. how many of each animal are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430638 by </B><A HREF=/tutors/aboutme.mpl?userid=Simnepi><B>Simnepi(216)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Simnepi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Simnepi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have to make two equations and solve them together.<BR>\n" );
document.write( "Let the number of chickens be called c and let the number of pigs be p.<BR>\n" );
document.write( "there are 13 animals in the barn so <BR>\n" );
document.write( "p + c = 13 this is equation 1.<BR>\n" );
document.write( "Since pigs have 4 legs the number of legs that the pigs have altogether is 4p and similarly chickens only have 2 legs so the number of their legs will be 2c.<BR>\n" );
document.write( "so 2c + 4p = 40 this is equation 2<BR>\n" );
document.write( "using equation 1 we can see that c = 13 - p<BR>\n" );
document.write( "putting this value into equation 2 and solving<BR>\n" );
document.write( "2X(13-p) + 4p = 40<BR>\n" );
document.write( "26-2p+4p = 40<BR>\n" );
document.write( "2p = 14<BR>\n" );
document.write( "p = 7 there are 7 pigs<BR>\n" );
document.write( "hence there are 6 chickens </SPAN>\n" );
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