document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=698415>Question 698415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i do these using substitution?\r<BR>\n" );
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document.write( "1. 2x-y=-6<BR>\n" );
document.write( "   4x+y=-6\r<BR>\n" );
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document.write( "2. 2x-y=3<BR>\n" );
document.write( "   4x-y=-1\r<BR>\n" );
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document.write( "3. 6x-5y=-1<BR>\n" );
document.write( "   5x-4y=-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430635 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430635\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do i do these using substitution?\r<BR>\n" );
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document.write( "1. 2x-y=-6<BR>\n" );
document.write( "   4x+y=-6<BR>\n" );
document.write( "Solve for y in either eqn, sub for it in the other eqn.<BR>\n" );
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document.write( "2. 2x-y=3<BR>\n" );
document.write( "   4x-y=-1<BR>\n" );
document.write( "Same as #1.<BR>\n" );
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document.write( "3. 6x-5y=-1<BR>\n" );
document.write( "   5x-4y=-1<BR>\n" );
document.write( "Solve for either x or y, then sub in the other eqn. </SPAN>\n" );
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