document.write( "Question 698409: Three straight paths in a park form a triangle with vertices at: A(-24,16) B(56,-16) and C(-72,-32).
\n" ); document.write( "determine the area of triangle ABC
\n" ); document.write( "hint: you will have to find the length of an altitude and the area of any triangle is half base of the triangle times it's height\r
\n" ); document.write( "\n" ); document.write( "i have no clue on how to do this \n" ); document.write( "
Algebra.Com's Answer #430630 by Alan3354(69443)\"\" \"About 
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Three straight paths in a park form a triangle with vertices at: A(-24,16) B(56,-16) and C(-72,-32).
\n" ); document.write( "determine the area of triangle ABC
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\n" ); document.write( "Do it like this.
\n" ); document.write( ".A......B.....C.....A
\n" ); document.write( "-24 +56 -72 -24
\n" ); document.write( "+16 -16 -32 +16
\n" ); document.write( "-------------
\n" ); document.write( "Add the diagonal products starting upper left.
\n" ); document.write( "-24*-`16 + 56*-32 + -72*16 = 384 - 1792 - 1152 = -2560
\n" ); document.write( "Add the diagonal products starting lower left.
\n" ); document.write( "16*56 + -16*-72 + -32*-16 = 896 + 1152 + 512 = 2560
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\n" ); document.write( "The area = 1/2 the difference = 2560 sq units
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\n" ); document.write( "It's a different method, not well known.
\n" ); document.write( "It works for polygons with any number of sides.
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