document.write( "Question 7850: I've been working on this for about 15 minutes now and I can not seem to find an answer. Please help.\r
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document.write( " The Murrays have invested money in two accounts. One pays 7% interest and the other pays 8.5% interest. They invested $1000 more at 8.5% than they invested at 7%. If the total interest earned in one year is $395, how much money have they invested in each account. \n" );
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Algebra.Com's Answer #4306 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let x = amount invested at 7%, then x+$1,000 = the amount invested at 8.5%. \n" ); document.write( "Total interest earned = $395.00. Change the percents to decimals.\r \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the Murrays invested $2,000.00 at 7% interest and $3,000.00 at 8.5% interest.\r \n" ); document.write( "\n" ); document.write( "Check: \r \n" ); document.write( "\n" ); document.write( "0.07($2,000.00) + 0.085($3,000.00) = $140.00 + $255.00 = $395.00\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |