document.write( "Question 698323: A jet takes 6 hours to travel a distance of 5400 miles against the wind. The return trip takes 5 hours with the wind. What is the rate of the jet in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #430591 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A jet takes 6 hours to travel a distance of 5400 miles against the wind. The return trip takes 5 hours with the wind. What is the rate of the jet in still air and what is the rate of the wind? \n" ); document.write( "** \n" ); document.write( "let x=rate of jet in still air \n" ); document.write( "let c=rate of wind \n" ); document.write( "x+c=rate downwind \n" ); document.write( "x-c=rate against wind \n" ); document.write( "** \n" ); document.write( "Distance/travel time=rate \n" ); document.write( "5400/6=x-c \n" ); document.write( "5400/5=x+c \n" ); document.write( ".. \n" ); document.write( "900=x-c \n" ); document.write( "1080=x+c \n" ); document.write( "add \n" ); document.write( "1980=2x \n" ); document.write( "x=990 \n" ); document.write( "c=x-900 \n" ); document.write( "c=90 \n" ); document.write( "rate of jet in still air=990 mph \n" ); document.write( "rate of wind=90 mph \n" ); document.write( " \n" ); document.write( " |