document.write( "Question 698323: A jet takes 6 hours to travel a distance of 5400 miles against the wind. The return trip takes 5 hours with the wind. What is the rate of the jet in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #430591 by lwsshak3(11628)\"\" \"About 
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A jet takes 6 hours to travel a distance of 5400 miles against the wind. The return trip takes 5 hours with the wind. What is the rate of the jet in still air and what is the rate of the wind?
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\n" ); document.write( "let x=rate of jet in still air
\n" ); document.write( "let c=rate of wind
\n" ); document.write( "x+c=rate downwind
\n" ); document.write( "x-c=rate against wind
\n" ); document.write( "**
\n" ); document.write( "Distance/travel time=rate
\n" ); document.write( "5400/6=x-c
\n" ); document.write( "5400/5=x+c
\n" ); document.write( "..
\n" ); document.write( "900=x-c
\n" ); document.write( "1080=x+c
\n" ); document.write( "add
\n" ); document.write( "1980=2x
\n" ); document.write( "x=990
\n" ); document.write( "c=x-900
\n" ); document.write( "c=90
\n" ); document.write( "rate of jet in still air=990 mph
\n" ); document.write( "rate of wind=90 mph
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