document.write( "Question 698158: what is a possible equation for a hyperbola that is centered at the origin, opens left and right and has a transverse axis of length 6 \n" ); document.write( "
Algebra.Com's Answer #430586 by KMST(5328)\"\" \"About 
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A hyperbola that is centered at the origin, and opens left and right has an equation of the form
\n" ); document.write( "\"x%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1\"
\n" ); document.write( "where \"x\" cannot be zero (because it would mean \"-y%5E2%2Fb%5E2=1\"<--->\"y%5E2%2Fb%5E2=-1\",
\n" ); document.write( "but when \"y=0\", \"x%5E2%2Fa%5E2=1\"<--->\"x%5E2=a%5E2\", so \"x=a\" or \"x=-a\" Those are the x-coordinates of vertices (-a,0) and (a,0),
\n" ); document.write( "and the distance between the vertices is the transverse axis = \"2a\"
\n" ); document.write( "So the equation you need is
\n" ); document.write( "\"highlight%28x%5E2%2F3%5E2-y%5E2%2Fb%5E2=1%29\" or \"highlight%28x%5E2%2F9-y%5E2%2Fb%5E2=1%29\"
\n" ); document.write( "You can chose a value for \"b%5E2\" to change how \"pointy\" the vertices are.
\n" ); document.write( "The slopes of the asymptotes will be \"b%2Fa\" and \"-b%2Fa\"
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