document.write( "Question 698243: I am in math091 at college and I am having issues solving(2x-3)^4\r
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document.write( "The only two answers I have figured out is 16x^4-81 and 16x^4+81 \n" );
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Algebra.Com's Answer #430582 by Edwin Parker(36)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "(2x-3)4\r\n" ); document.write( "\r\n" ); document.write( "Here's how to do it, and the principle works for all cases of (A+B)N.\r\n" ); document.write( "I'll go through every step in great detail. But you will learn to shorten\r\n" ); document.write( "the process by combining steps and doing some of the easy parts in your head:\r\n" ); document.write( "\r\n" ); document.write( "The power is 4. 1 more than 4 is five, so write (2x) (-3) five times\r\n" ); document.write( "with + signs between\r\n" ); document.write( "\r\n" ); document.write( " (2x) (-3) + (2x) (-3) + (2x) (-3) + (2x) (-3) + (2x) (-3) \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From left to right put the exponents 4,3,2,1,0 on the (2x)'s\r\n" ); document.write( "\r\n" ); document.write( " (2x)4(-3) + (2x)3(-3) + (2x)2(-3) + (2x)1(-3) + (2x)0(-3)\r\n" ); document.write( "\r\n" ); document.write( "From left to right put the exponents 0,1,2,3,4 on the (-3)'s\r\n" ); document.write( "\r\n" ); document.write( " (2x)4(-3)0 + (2x)3(-3)1 + (2x)2(-3)2 + (2x)1(-3)3 + (2x)0(-3)4\r\n" ); document.write( "\r\n" ); document.write( "Put a 1 coefficient before the 1st term:\r\n" ); document.write( "\r\n" ); document.write( "1(2x)4(-3)0 + (2x)3(-3)1 + (2x)2(-3)2 + (2x)1(-3)3 + (2x)0(-3)4\r\n" ); document.write( "\r\n" ); document.write( "Look at 1st term. Multiply that 1 coefficient by the exponent of (2x), which is 4, \r\n" ); document.write( "getting 1×4 = 4 and divide that 4 by 1 since that is the 1st term, getting 4. \r\n" ); document.write( "\r\n" ); document.write( "Put a 4 coefficient before the 2nd term\r\n" ); document.write( "\r\n" ); document.write( "1(2x)4(-3)0 + 4(2x)3(-3)1 + (2x)2(-3)2 + (2x)1(-3)3 + (2x)0(-3)4\r\n" ); document.write( "\r\n" ); document.write( "Look at 2nd term. Multiply that 4 coefficient by the exponent of (2x), which\r\n" ); document.write( "is 3, getting 4×3 = 12 and divide that 12 by 2 since that is the 2nd term, getting 6. \r\n" ); document.write( "\r\n" ); document.write( "Put a 6 coefficient before the 3rd term\r\n" ); document.write( "\r\n" ); document.write( "1(2x)4(-3)0 + 4(2x)3(-3)1 + 6(2x)2(-3)2 + (2x)1(-3)3 + (2x)0(-3)4\r\n" ); document.write( "\r\n" ); document.write( "Look at 3rd term. Multiply that 6 coefficient by the exponent of (2x), which\r\n" ); document.write( "is 2, getting 6×2 = 12 and divide that 12 by 3 since that is the 3rd term, getting 4. \r\n" ); document.write( "\r\n" ); document.write( "Put a 4 coefficient before the 4th term\r\n" ); document.write( "\r\n" ); document.write( "1(2x)4(-3)0 + 4(2x)3(-3)1 + 6(2x)2(-3)2 + 4(2x)1(-3)3 + (2x)0(-3)4\r\n" ); document.write( "\r\n" ); document.write( "Look at 4th term. Multiply that 4 coefficient by the exponent of (2x), which\r\n" ); document.write( "is 1, getting 4×1 = 4 and divide that 4 by 4 since that is the 4th term, getting 1. \r\n" ); document.write( "\r\n" ); document.write( "Put a 1 coefficient before the 5th term.\r\n" ); document.write( "\r\n" ); document.write( "1(2x)4(-3)0 + 4(2x)3(-3)1 + 6(2x)2(-3)2 + 4(2x)1(-3)3 + 1(2x)0(-3)4\r\n" ); document.write( "\r\n" ); document.write( "That's the answer except for simplifying:\r\n" ); document.write( "\r\n" ); document.write( "We can erase the 1 coefficients and the 1 exponents. We can also erase the \r\n" ); document.write( "factors with 0 exponents since they are 1. Finish simplifying:\r\n" ); document.write( "\r\n" ); document.write( "(2x)4 + 4(2x)3(-3) + 6(2x)2(-3)2 + 4(2x)(-3)3 + (-3)4\r\n" ); document.write( "\r\n" ); document.write( "16x4 + 4(8x3)(-3) + 6(4x2)(9) +4(2x)(-27) +(-3)4\r\n" ); document.write( "\r\n" ); document.write( "16x4 - 96x3 + 216x2 - 216x + 81 \r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |