document.write( "Question 698126: the length of a rectangle is 5 centimeters more than its width. if the perimeter of the rectangle is 26 centimeters what is the area of the rectangle, in square centimeters \n" ); document.write( "

Algebra.Com's Answer #430450 by Stitch(470) $\"\"$ $\"About$

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Set-Up
\n" ); document.write( "--------------
\n" ); document.write( "L = length
\n" ); document.write( "W = width
\n" ); document.write( "The perimiter of a rectangle is given by P = 2L + 2W
\n" ); document.write( "Given: P = 26
\n" ); document.write( "Equation 1: $\"26+=+2L+%2B+2W\"$
\n" ); document.write( "Equation 2: $\"L+=+W+%2B+5\"$ \r
\n" ); document.write( "\n" ); document.write( "Solution:
\n" ); document.write( "--------------
\n" ); document.write( "Plug (W + 5) into equation 1 for L
\n" ); document.write( "Equation 1: $\"26+=+2L+%2B+2W\"$
\n" ); document.write( " $\"26+=+2%2A%28W+%2B+5%29+%2B+2W\"$
\n" ); document.write( "Simplify
\n" ); document.write( " $\"26+=+2W+%2B+10+%2B+2W\"$
\n" ); document.write( "Simplify
\n" ); document.write( " $\"26+=+4W+%2B+10\"$
\n" ); document.write( "Subtract 10 from both sides
\n" ); document.write( " $\"16+=+4W\"$
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( " $\"highlight%284+=+W%29\"$
\n" ); document.write( "Now plug 4 into equation 2 for W
\n" ); document.write( "Equation 2: $\"L+=+W+%2B+5\"$
\n" ); document.write( " $\"L+=+%284%29+%2B+5\"$
\n" ); document.write( " $\"highlight_green%28L+=+9%29\"$
\n" ); document.write( "-------------------------------
\n" ); document.write( "The equation for the area of a rectangle is A = L*W
\n" ); document.write( "So: $\"A+=+9+%2A+4\"$
\n" ); document.write( " $\"highlight%28A+=+36%29\"$
\n" ); document.write( "The area of the rectangle is 36 square centimeters\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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