document.write( "Question 698033: can you help me \"find three consecutive integers such that the first added to 3 times the second is 83\" \n" ); document.write( "
Algebra.Com's Answer #430419 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let represent the first integer. Then next consecutive integer is then and the third must be .\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Three times the second is then .\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The first added to three times the second is then \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And the whole thing is equal to 83:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve for , then calculate and \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "
\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "
\"The

\n" ); document.write( "
\n" ); document.write( "
\n" );