document.write( "Question 697811: Jacob travelled 225 km to deliver goods from a factory. Had he travelled 15 kph more, he could make the trip in 1 ¼ hours less time and could have gone back to the factory earlier than usual. What is Jacob’s usual speed? \n" ); document.write( "
Algebra.Com's Answer #430404 by ankor@dixie-net.com(22740)\"\" \"About 
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Jacob traveled 225 km to deliver goods from a factory.
\n" ); document.write( " Had he traveled 15 kph more, he could make the trip in 1 ¼ hours less time and could have gone back to the factory earlier than usual.
\n" ); document.write( " What is Jacob’s usual speed?
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\n" ); document.write( "Let s = his usual speed
\n" ); document.write( "then
\n" ); document.write( "(s+15) = the faster speed
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\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Normal time - Faster time = 1.25 hrs
\n" ); document.write( "\"225%2Fs\" - \"225%2F%28%28s%2B15%29%29\" = 1.25
\n" ); document.write( "Multiply by s(s+15),resulting in:
\n" ); document.write( "225(s+15)- 225s = 1.25s(s+15)
\n" ); document.write( "225s + 3375 - 225s = 1.25s^2 + 18.75s
\n" ); document.write( "A quadratic equation
\n" ); document.write( "1.25s^2 + 18.75s - 3375 = 0
\n" ); document.write( "multiplying by 4 gets rid of the decimals, we have
\n" ); document.write( "5s^2 + 75s - 13500 = 0
\n" ); document.write( "now we can simplify this, divide by 5
\n" ); document.write( "s^2 + 15s - 2700 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(s-45)(s+60) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "s = 45 km/h is his usual speed
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\n" ); document.write( "Confirm this by finding the time at each speed
\n" ); document.write( "225/45 = 5 hrs
\n" ); document.write( "225.60 = 3.75 hrs
\n" ); document.write( "-------------------
\n" ); document.write( "time dif:1.25 hrs
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