document.write( "Question 697811: Jacob travelled 225 km to deliver goods from a factory. Had he travelled 15 kph more, he could make the trip in 1 ¼ hours less time and could have gone back to the factory earlier than usual. What is Jacob’s usual speed? \n" ); document.write( "
Algebra.Com's Answer #430404 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jacob traveled 225 km to deliver goods from a factory. \n" ); document.write( " Had he traveled 15 kph more, he could make the trip in 1 ¼ hours less time and could have gone back to the factory earlier than usual. \n" ); document.write( " What is Jacob’s usual speed? \n" ); document.write( ": \n" ); document.write( "Let s = his usual speed \n" ); document.write( "then \n" ); document.write( "(s+15) = the faster speed \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "Normal time - Faster time = 1.25 hrs \n" ); document.write( " \n" ); document.write( "Multiply by s(s+15),resulting in: \n" ); document.write( "225(s+15)- 225s = 1.25s(s+15) \n" ); document.write( "225s + 3375 - 225s = 1.25s^2 + 18.75s \n" ); document.write( "A quadratic equation \n" ); document.write( "1.25s^2 + 18.75s - 3375 = 0 \n" ); document.write( "multiplying by 4 gets rid of the decimals, we have \n" ); document.write( "5s^2 + 75s - 13500 = 0 \n" ); document.write( "now we can simplify this, divide by 5 \n" ); document.write( "s^2 + 15s - 2700 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(s-45)(s+60) = 0 \n" ); document.write( "the positive solution \n" ); document.write( "s = 45 km/h is his usual speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the time at each speed \n" ); document.write( "225/45 = 5 hrs \n" ); document.write( "225.60 = 3.75 hrs \n" ); document.write( "------------------- \n" ); document.write( "time dif:1.25 hrs \n" ); document.write( " |