document.write( "Question 697920: The length of a rectangle is two less than six times its width. The perimeter in 66 cm. Find the length and width of the rectangle. I am stuck. I keep getting here: 70=16w so w=4.375 and l=24.25. But when I do this it adds up to: 57.25 not 66 \n" ); document.write( "
Algebra.Com's Answer #430363 by lwsshak3(11628)\"\" \"About 
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The length of a rectangle is two less than six times its width. The perimeter in 66 cm. Find the length and width of the rectangle.
\n" ); document.write( "**
\n" ); document.write( "let W=width
\n" ); document.write( "let L=length
\n" ); document.write( "..
\n" ); document.write( "L=6W-2
\n" ); document.write( "2W+2L=perimeter
\n" ); document.write( "2W+2(6W-2)=66
\n" ); document.write( "2W+12W-4=66
\n" ); document.write( "14W=70
\n" ); document.write( "W=70/14
\n" ); document.write( "W=5
\n" ); document.write( "L=6W-2=
\n" ); document.write( "L=30-2
\n" ); document.write( "L=28
\n" ); document.write( "Check:
\n" ); document.write( "perimeter=2L+2W=56+10=66 \n" ); document.write( "
\n" );