document.write( "Question 62240This question is from textbook alegbra concepts and applications
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document.write( ": I really need help to solve the following\r
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document.write( "-k(-2-3) - (-2)(-k-5) = -2-(-2k+4) + 3 times the square root of -27 \n" );
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Algebra.Com's Answer #43036 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! -k(-2-3) - (-2)(-k-5) = -2-(-2k+4) + 3 times the square root of -27 \n" ); document.write( ": \n" ); document.write( "-k(-2-3) - (-2)(-k-5) = -2 - 1(-2k+4) + 3*SqRt(-27) \n" ); document.write( ": \n" ); document.write( "k(-2-3) - (-2)(-k-5) = -2 - 1(-2k+4) + 3*SqRt(3*3*3*-1) \n" ); document.write( ": \n" ); document.write( "-k(-5) + 2(-k-5) = -2 + 2k - 4 + 3*3i*SqRt(3) \n" ); document.write( ": \n" ); document.write( "+5k - 2k - 5 = - 2 + 2k - 4 + 9i*SqRt(3) \n" ); document.write( ": \n" ); document.write( "5k - 2k - 2k = - 6 + 5 + 9i*SqRt(3) \n" ); document.write( ": \n" ); document.write( "k = -1 + 9i*SqRt(3) \n" ); document.write( ": \n" ); document.write( "The main thing is watch the signs and change them if there is a neg outside the brackets. I guess you know that i = SqRt(-1) \n" ); document.write( " |