document.write( "Question 697872: the sum of the ages of two persons A and B is 50. 5 years ago,the ratio of their ages was 5/3. the present age of A and B are
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #430307 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
the sum of the ages of two persons A and B is 50. 5 years ago,the ratio of their ages was 5/3. the present age of A and B are
\n" ); document.write( "-----
\n" ); document.write( "Equations:
\n" ); document.write( "a + b = 50
\n" ); document.write( "(a-5)/(b-5) = 5/3
\n" ); document.write( "-------
\n" ); document.write( "Substitute for \"a\" and solve for \"b\":
\n" ); document.write( "a = 50-b
\n" ); document.write( "----
\n" ); document.write( "(50-b-5)/(b-5) = 5/3
\n" ); document.write( "----
\n" ); document.write( "3(45-b) = 5(b-5)
\n" ); document.write( "135 - 3b = 5b - 25
\n" ); document.write( "8b = 160
\n" ); document.write( "b = 20
\n" ); document.write( "Then a = 30
\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );