document.write( "Question 697720: At some stops, a certain bus picks up 5 people. At other stops, it picks up 2 and, at the same time lets off 5. There are no other stops but these. It starts its run empty and picks up 5 people. At the end, it has 11 people aboard.\r
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document.write( "a. If the number of stops is greater than 75, what is the least number of stops the bus makes?\r
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document.write( "b. If the number of stops is greater than 703, what is the least number of stops the bus makes?\r
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document.write( "c. For part A, how many of the stops must be where the total gain in passengers is 5? For part B? \n" );
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Algebra.Com's Answer #430270 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! At some stops, a certain bus picks up 5 people. At other stops, it picks up 2 and, at the same time lets off 5. \n" ); document.write( " \r\n" ); document.write( "Let x = the number of times the bus increases the no. of passengers by 5.\r\n" ); document.write( "\r\n" ); document.write( "When the bus picks up 2 and lets off 5, it decreases the no. of passengers\r\n" ); document.write( "by 3.\r\n" ); document.write( "\r\n" ); document.write( "Let y = the number of times the bus decreases the no. of passengers by 3.\r\n" ); document.write( "\r\n" ); document.write( "Then the number of passengers is 5x - 3y \r\n" ); document.write( " \n" ); document.write( "There are no other stops but these. It starts its run empty and picks up 5 people. At the end, it has 11 people aboard. \n" ); document.write( " \r\n" ); document.write( "So we have\r\n" ); document.write( " 5x - 3y = 11\r\n" ); document.write( "\r\n" ); document.write( "The smallest coefficient in absolute value is |-3| = 3.\r\n" ); document.write( "\r\n" ); document.write( "So we write 5 and ll in terms of their nearest multiple of 3.\r\n" ); document.write( "\r\n" ); document.write( "The nearest multiple of 3 to 5 is 6, so we write 5 as 6-1,\r\n" ); document.write( "The nearest multiple of 3 to 11 is 12, so we write 11 as 12-1, \r\n" ); document.write( "\r\n" ); document.write( " (6-1)x - 3y = 12-1\r\n" ); document.write( " 6x - x - 3y = 12 - 1\r\n" ); document.write( "\r\n" ); document.write( "Divide every term through by 3\r\n" ); document.write( "\r\n" ); document.write( " 2x - \n" ); document.write( "a. If the number of stops is greater than 75, what is the least number of stops the bus makes? \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " x + y > 75\r\n" ); document.write( "\r\n" ); document.write( "Substitute (x,y) = (3A+1,5A-2)\r\n" ); document.write( "\r\n" ); document.write( " 3A+1 + 5A-2 > 75\r\n" ); document.write( " 8A-1 > 75\r\n" ); document.write( " 8A > 76\r\n" ); document.write( " A > \n" ); document.write( "b. If the number of stops is greater than 703, what is the least number of stops the bus makes? \n" ); document.write( " \r\n" ); document.write( " x + y > 703\r\n" ); document.write( "\r\n" ); document.write( "Substitute (x,y) = (3A+1,5A-2)\r\n" ); document.write( "\r\n" ); document.write( " 3A+1 + 5A-2 > 703\r\n" ); document.write( " 8A-1 > 703\r\n" ); document.write( " 8A > 704\r\n" ); document.write( " A > \n" ); document.write( "c. For part A, how many of the stops must be where the total gain in passengers is 5? \n" ); document.write( " \r\n" ); document.write( "That's just the value of x for part a, which is 31.\r\n" ); document.write( " \n" ); document.write( "For part B? \n" ); document.write( " \r\n" ); document.write( "That's just the value of x for part b, which is 268.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |