document.write( "Question 62290: this is for college algebra: find a polynomial of lowest degree that has real coefficients, a leading coefficient of 1, and with 5-2i and 3 as two of its zeros \n" ); document.write( "
Algebra.Com's Answer #43025 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find a polynomial of lowest degree that has real coefficients, a leading coefficient of 1, and with 5-2i and 3 as two of its zeroes. \n" ); document.write( "-------- \n" ); document.write( "If 5-2i is a zero and it has real coefficients then 5+2i is also \n" ); document.write( "a zero. \n" ); document.write( "So f(x)=(x-3)(x-(5-2i))(x-(5+2i)) \n" ); document.write( "f(x)= (x-3)((x-5)^2+4) \n" ); document.write( "f(x)= (x-3)(x^2-10x+29) \n" ); document.write( "f(x)=x^3-10x^2-3x^2+29x-30x-12 \n" ); document.write( "f(x)=x^3-13x^2-x-12 \n" ); document.write( "Cheers, \n" ); document.write( "stan H. \n" ); document.write( " |