document.write( "Question 697652: leaving from her home, mindy jogged at the rate 4 mph and walked back at the rate 2 mph. if she spent a total of 6 hours on her trip without stopping, how far did her trip take her from home ? \n" ); document.write( "

Algebra.Com's Answer #430249 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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leaving from her home, mindy jogged at the rate 4 mph and walked back at the rate 2 mph.
\n" ); document.write( " if she spent a total of 6 hours on her trip without stopping, how far did her trip take her from home ?
\n" ); document.write( ":
\n" ); document.write( "let d = the one-way distance
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\n" ); document.write( "Write a time equation; Time = dist/speed
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\n" ); document.write( "Jog time + walk time = 6 hrs
\n" ); document.write( " $\"d%2F4\"$ + $\"d%2F2\"$ = 6
\n" ); document.write( "multiply by 4, to clear the denominators, results:
\n" ); document.write( "d + 2d = 4(6)
\n" ); document.write( "3d = 24
\n" ); document.write( "d = 24/3
\n" ); document.write( "d = 8 miles from home
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the time of each way.
\n" ); document.write( "8/4 = 2hrs
\n" ); document.write( "8/2 = 4hrs
\n" ); document.write( "------------
\n" ); document.write( "total: 6 hrs \n" ); document.write( "

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