document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=697698>Question 697698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many odd numbers of three digits each can be formed from the digits 2,4,6 and 7 if repetition of digits is permitted. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430229 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20055)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Odd numbers end in an odd digit.  There is just one odd digit, 7,<BR>\n" );
document.write( "so we can choose the third digit just 1 way.\r<BR>\n" );
document.write( "\n" );
document.write( " <BR>\n" );
document.write( "we can choose the 1st digit any of 4 ways<BR>\n" );
document.write( "we can choose the 2nd digit any of 4 ways <BR>\n" );
document.write( "we can choose the 3rd digit just 1 way (as 7),\r<BR>\n" );
document.write( "\n" );
document.write( "So the number of ways is 4󫶕 = 16 ways\r<BR>\n" );
document.write( "\n" );
document.write( "They are:\r<BR>\n" );
document.write( "\n" );
document.write( "227, 247, 267, 277,<BR>\n" );
document.write( "427, 447, 467, 477,<BR>\n" );
document.write( "627, 647, 667, 677,<BR>\n" );
document.write( "727, 747, 767, 777.\r<BR>\n" );
document.write( "\n" );
document.write( "Edwin</pre> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );