document.write( "Question 697680: how do you find the perimeter of a non right triangle using the pythagorean theorem\r
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Algebra.Com's Answer #430215 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Suppose you know one side and two angles, say,\r\n" );
document.write( "AB = 10, Angle B = 42°, Angle C = 32° \r\n" );
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document.write( "Draw perpendicular AD from A to BC\r\n" );
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document.write( "\"AD%2FAB\" = sin(42°)\r\n" );
document.write( "\"AD%2F10\" = sin(42°)\r\n" );
document.write( "AD = 10·sin(42°)\r\n" );
document.write( "AD = 6.69\r\n" );
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document.write( "\"AD%2FAC\" = sin(32°)\r\n" );
document.write( "\"6.69%2FAC\" = sin(32°)\r\n" );
document.write( "AC·sin(32°) = 6.69\r\n" );
document.write( "AC = \"6.69%2Fsin%28%2232%B0%22%29\"\r\n" );
document.write( "AC = 12.62\r\n" );
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document.write( "Use the Pythagorean theorem to find BD\r\n" );
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document.write( "BD˛ + AD˛ = AB˛\r\n" );
document.write( "      BD˛ = AB˛ - AD˛\r\n" );
document.write( "      BD˛ = 10˛ - 6.69˛\r\n" );
document.write( "      BD˛ = 55.2439\r\n" );
document.write( "      BD = √55.2439\r\n" );
document.write( "      BD = 7.43\r\n" );
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document.write( "Use the Pythagorean theorem to find DC\r\n" );
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document.write( "DC˛ + AD˛ = AC˛\r\n" );
document.write( "      DC˛ = AC˛ - AD˛\r\n" );
document.write( "      DC˛ = (12.62)˛ - (6.69)˛\r\n" );
document.write( "      DC˛ = 114.5083\r\n" );
document.write( "       DC = √114.5083\r\n" );
document.write( "       DC = 10.70\r\n" );
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document.write( "We have side AB = 10, side AC = 12.63, and since we have\r\n" );
document.write( "BD = 7.43 and DC = 10.70, we have side BC = BD+DC = 7.43+10.70 = 18.13\r\n" );
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document.write( "So we can find the perimeter AB + BC + AC = 10 + 18.13 + 12.62 = 40.75\r\n" );
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document.write( "Edwin

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