document.write( "Question 697495: Elmore and Sonjay cross-country skied along the same trail. Sonjay skied at 12ft/s. Elmore skied at 15ft/s and started down the trail 2 min after Sonjay started. The two skiers reached the first fork in the trail at the same time.\r
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document.write( "a. How long after Sonjay started did the two skiers meet?\r
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document.write( "b. How far was it to the first fork? \n" );
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Algebra.Com's Answer #430213 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Elmore and Sonjay cross-country skied along the same trail. \n" ); document.write( " Sonjay skied at 12ft/s. \n" ); document.write( "Elmore skied at 15ft/s and started down the trail 2 min after Sonjay started. \n" ); document.write( " The two skiers reached the first fork in the trail at the same time. \n" ); document.write( ": \n" ); document.write( "a. How long after Sonjay started did the two skiers meet? \n" ); document.write( "Change 2 min to 120 sec \n" ); document.write( "let t = S's skiing time \n" ); document.write( "then \n" ); document.write( "(t-120) = E's skiing time \n" ); document.write( ": \n" ); document.write( "When E catches S, they will have traveled the same dist \n" ); document.write( "write distance equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "E's dist = S's dist \n" ); document.write( "15(t-120) = 12t \n" ); document.write( "15t - 1800 = 1t \n" ); document.write( "15t - 12t = 1800 \n" ); document.write( "3t = 1800 \n" ); document.write( "t = 600 secs (10 min) after S starts, is caught by E \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "b. How far was it to the first fork? \n" ); document.write( "12(600) = 7200 ft \n" ); document.write( "check \n" ); document.write( "15(600-120) = 7200 ft \n" ); document.write( " |