document.write( "Question 697495: Elmore and Sonjay cross-country skied along the same trail. Sonjay skied at 12ft/s. Elmore skied at 15ft/s and started down the trail 2 min after Sonjay started. The two skiers reached the first fork in the trail at the same time.\r
\n" ); document.write( "\n" ); document.write( "a. How long after Sonjay started did the two skiers meet?\r
\n" ); document.write( "\n" ); document.write( "b. How far was it to the first fork?
\n" ); document.write( "

Algebra.Com's Answer #430213 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Elmore and Sonjay cross-country skied along the same trail.
\n" ); document.write( " Sonjay skied at 12ft/s.
\n" ); document.write( "Elmore skied at 15ft/s and started down the trail 2 min after Sonjay started.
\n" ); document.write( " The two skiers reached the first fork in the trail at the same time.
\n" ); document.write( ":
\n" ); document.write( "a. How long after Sonjay started did the two skiers meet?
\n" ); document.write( "Change 2 min to 120 sec
\n" ); document.write( "let t = S's skiing time
\n" ); document.write( "then
\n" ); document.write( "(t-120) = E's skiing time
\n" ); document.write( ":
\n" ); document.write( "When E catches S, they will have traveled the same dist
\n" ); document.write( "write distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "E's dist = S's dist
\n" ); document.write( "15(t-120) = 12t
\n" ); document.write( "15t - 1800 = 1t
\n" ); document.write( "15t - 12t = 1800
\n" ); document.write( "3t = 1800
\n" ); document.write( "t = 600 secs (10 min) after S starts, is caught by E
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "b. How far was it to the first fork?
\n" ); document.write( "12(600) = 7200 ft
\n" ); document.write( "check
\n" ); document.write( "15(600-120) = 7200 ft
\n" ); document.write( "
\n" );