document.write( "Question 697637: \r
\n" ); document.write( "\n" ); document.write( "if a child walks at 5 km/h from his house and reaches his school 3 minutes late.however,if he walks at 6km/h,he reaches 5 minutes early.how far is the school from his house?
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Algebra.Com's Answer #430181 by checkley79(3341)\"\" \"About 
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D=RT
\n" ); document.write( "D=5(T+3)
\n" ); document.write( "D=6(T-5)
\n" ); document.write( "5(T+3)=6(T-5)
\n" ); document.write( "5T+15=6T-30
\n" ); document.write( "5T-6T=-30-15
\n" ); document.write( "-T=-45
\n" ); document.write( "T=45 MINUTES IS THE TIME.
\n" ); document.write( "PROOF:
\n" ); document.write( "5(45+3)=6(45-5)
\n" ); document.write( "5*48=6*40
\n" ); document.write( "240=240
\n" ); document.write( "D=5(45+3) 5 KM/H* 48 MIN.
\n" ); document.write( "D=5*.8
\n" ); document.write( "D=4 KM. DISTANCE TO THE SCHOOL.
\n" ); document.write( "D=6(45-5) 6KM/H* 40 MIN.
\n" ); document.write( "D=6*2/3
\n" ); document.write( "D=12/3=4 KM. DITTO.
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