document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=697547>Question 697547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Four boys step off from the same place.If their steps measure 16cm, 28cm40cm and 77cm respectively,at what distance from the starting point will they again steo together </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430116 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Four boys step off from the same place.If their steps measure 16cm, 28cm 40cm and 77cm respectively,<BR>\n" );
document.write( "at what distance from the starting point will they again step together?<BR>\n" );
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document.write( "Prime factor each value<BR>\n" );
document.write( "16: 2*2*2*2<BR>\n" );
document.write( "28: 2*2*7<BR>\n" );
document.write( "40: 2*2*2*5<BR>\n" );
document.write( "77: 7*11<BR>\n" );
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document.write( "Least common multiple 2*2*2*2*5*7*11 = 6160 cm they should be in step again<BR>\n" );
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document.write( "AT that time:<BR>\n" );
document.write( " 1st boy will take: 385 steps<BR>\n" );
document.write( " 2nd boy will take: 220 steps<BR>\n" );
document.write( " 3rd boy will take: 154 steps<BR>\n" );
document.write( " 4th boy will take: 80 steps </SPAN>\n" );
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