document.write( "Question 62109This question is from textbook Applied College Algebra
\n" ); document.write( ": Solve using elimination: 5x + 3y = 28
\n" ); document.write( " 2x + 4Y = - 4 \n" ); document.write( "
Algebra.Com's Answer #43009 by ankor@dixie-net.com(22740)\"\" \"About 
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Solve using elimination:
\n" ); document.write( ":
\n" ); document.write( "5x + 3y = 28
\n" ); document.write( "2x + 4Y = - 4
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by 4, and the 2nd equation by 3, resulting in:
\n" ); document.write( "20x + 12y = 112
\n" ); document.write( "6x + 12y = -12
\n" ); document.write( "--------------------subtracting eliminates y
\n" ); document.write( "14x + 0y = +124
\n" ); document.write( "x = 124/14
\n" ); document.write( "x = 62/7
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\n" ); document.write( "Find y using the 1st equation:
\n" ); document.write( "5(62/7) + 3y = 28
\n" ); document.write( "(310/7) + 3y = 28
\n" ); document.write( "3y = 28 - (310/7)
\n" ); document.write( "3y = (196/7) - (310/7)
\n" ); document.write( "3y = -114/7
\n" ); document.write( "y = -38/7
\n" ); document.write( ":
\n" ); document.write( "Check solution in the 2nd equation
\n" ); document.write( "2(62/7) + 4(-38/7) = -4
\n" ); document.write( "(124/7) - (152/7) = -4
\n" ); document.write( "-28/7 = -4\r
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