document.write( "Question 692221: i don't know how to do this kind of problem. (2/3)x + 7 = (3/7) \n" ); document.write( "
Algebra.Com's Answer #430067 by mathbird(71)\"\" \"About 
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(2/3)x + 7 = (3/7)
\n" ); document.write( "(2/3)x=(3/7)-7
\n" ); document.write( "(2/3)x=-46/7
\n" ); document.write( "2x=-(46/7)*3
\n" ); document.write( "2x=-138/7
\n" ); document.write( "x=-69/7
\n" ); document.write( "
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