document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=697473>Question 697473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If one side of a square is tripled and another side is increased by 4cm,the area of the resulting rectangle is 180cm^2.What is the length of the side of the original square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430048 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let side of square be x\r<BR>\n" );
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document.write( "3x & x+4 are the new dimensions\r<BR>\n" );
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document.write( "Area = L * W\r<BR>\n" );
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document.write( "3x(x+4) = 180<BR>\n" );
document.write( "3x^2+12x=180<BR>\n" );
document.write( "3x^2+12x-180=0\r<BR>\n" );
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document.write( "/3<BR>\n" );
document.write( "x^2+4x-60=0\r<BR>\n" );
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document.write( "x^2+10x-4x-60=0<BR>\n" );
document.write( "x(x+10)-4(x+10)=0<BR>\n" );
document.write( "(x+10)(x-4)=0\r<BR>\n" );
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document.write( "x=-10 OR 4\r<BR>\n" );
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document.write( "x cannot be negative<BR>\n" );
document.write( "therefore the side of square is 4cm </SPAN>\n" );
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