document.write( "Question 697327: \"a-6%2Fa%2B15+=+2a%2F2a%2B6\" Please provide check. I really don't understand this, thank you so much in advance! \n" ); document.write( "
Algebra.Com's Answer #430041 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"a-6%2Fa%2B15+=+2a%2F2a%2B6\" Please provide check. I really don't understand this, thank you so much in advance! \r
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\n" ); document.write( "\n" ); document.write( "\"a+-+6%2Fa+%2B+15+=+2a%2F2a+%2B+6\"\r
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\n" ); document.write( "\n" ); document.write( "\"2a%2F2a\" is 1. Therefore, \"a+-+6%2Fa+%2B+15+=+2a%2F2a+%2B+6\" becomes: \"a+-+6%2Fa+%2B+15+=+1+%2B+6\". Are you sure this is how the problem was stated?\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2+-+6+%2B+15a+=+7a\" ------ Multiplying by LCD, a\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2+%2B+15a+-+7a+-+6+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2+%2B+8a+-+6+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "You can use the quadratic equation to solve, but for some reason, I believe that the problem was incorrectly stated. If so, say so in the thank-you note and I will redo.\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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