document.write( "Question 62270: The rectangular tabletop has a width that is two feet less than four times its length. If the area of the tabletop is 20ft^2, what are the dimensions of the tabletop? \n" ); document.write( "
Algebra.Com's Answer #43003 by tutorcecilia(2152)\"\" \"About 
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Area = (length)(width) [use the formula for the area of a rectangle]
\n" ); document.write( "Area = 20 ft^2
\n" ); document.write( "Length=L
\n" ); document.write( "Width=4L-2
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\n" ); document.write( "20=(L)(4L-2)[plug-in the values]
\n" ); document.write( "20=4L^2-2L [simplify]
\n" ); document.write( "0=4L^2-2L-20 [set the equation equal to zero and factor using the quadratic equation]
\n" ); document.write( ".
\n" ); document.write( "L=2.5[use this answer since it is a positive measurement]
\n" ); document.write( "L=-2.00 [eliminate this answer since measurements cannot be negative]
\n" ); document.write( ".
\n" ); document.write( "Length = 2.5
\n" ); document.write( "Width = 4L-2=(4)(2.5)-2=8
\n" ); document.write( ".
\n" ); document.write( "Check by plugging all of the values back into the formula for the area of a rectangle:
\n" ); document.write( "Area = (2.5)(8)
\n" ); document.write( "A=20 [checks out]
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