document.write( "Question 62270: The rectangular tabletop has a width that is two feet less than four times its length. If the area of the tabletop is 20ft^2, what are the dimensions of the tabletop? \n" ); document.write( "
Algebra.Com's Answer #43003 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! Area = (length)(width) [use the formula for the area of a rectangle] \n" ); document.write( "Area = 20 ft^2 \n" ); document.write( "Length=L \n" ); document.write( "Width=4L-2 \n" ); document.write( ". \n" ); document.write( "20=(L)(4L-2)[plug-in the values] \n" ); document.write( "20=4L^2-2L [simplify] \n" ); document.write( "0=4L^2-2L-20 [set the equation equal to zero and factor using the quadratic equation] \n" ); document.write( ". \n" ); document.write( "L=2.5[use this answer since it is a positive measurement] \n" ); document.write( "L=-2.00 [eliminate this answer since measurements cannot be negative] \n" ); document.write( ". \n" ); document.write( "Length = 2.5 \n" ); document.write( "Width = 4L-2=(4)(2.5)-2=8 \n" ); document.write( ". \n" ); document.write( "Check by plugging all of the values back into the formula for the area of a rectangle: \n" ); document.write( "Area = (2.5)(8) \n" ); document.write( "A=20 [checks out] \n" ); document.write( " |