document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=697456>Question 697456</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one of the two complementary angles measures 30 degrees more than three times the other. Find the measure of each angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430024 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one of the two complementary angles measures 30 degrees more than three times the other. Find the measure of each angle<BR>\n" );
document.write( "------<BR>\n" );
document.write( "1st angle: x<BR>\n" );
document.write( "2nd angle: 90-x<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "x = 3(90-x)+30<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "x = 270 - 3x + 30<BR>\n" );
document.write( "4x = 300<BR>\n" );
document.write( "x = 75 degrees<BR>\n" );
document.write( "90-x = 15 degrees<BR>\n" );
document.write( "=========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );