document.write( "Question 697451: A contractor rented a sander for 5 h and a polisher for 5h for $50. For another job, she rented the sander for 4 h and the polisher for 8 h. The rental fees for that job totalled $56. Find the hourly rate charged for each tool. \n" ); document.write( "
Algebra.Com's Answer #430009 by mananth(16946)![]() ![]() You can put this solution on YOUR website! x= cost per hour sander \n" ); document.write( "y= cost per hour polisher \n" ); document.write( "Total sold \n" ); document.write( "5 x + 5 y = 50 .............1 \n" ); document.write( " \n" ); document.write( "4 x + 8 y = 56 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -8 \n" ); document.write( "Multiply (2) by 5 \n" ); document.write( "-40 x -40 y = -400 \n" ); document.write( "20 x + 40 y = 280 \n" ); document.write( "Add the two equations \n" ); document.write( "-20 x = -120 \n" ); document.write( "/ -20 \n" ); document.write( "x = 6 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "5 x + 5 y = 50 \n" ); document.write( "30 + 5 y = 50 \n" ); document.write( " 5 y = 50 -30 \n" ); document.write( " 5 y = 20 \n" ); document.write( " y = 4 \n" ); document.write( " $6 cost per hour sander \n" ); document.write( " $4 cost per hour polisher \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |