document.write( "Question 697434: A laptop computer is purchased for $1200 . Each year, its value is 70% of its value the year before. After how many years will the laptop computer be worth $300 or less? \r
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\n" ); document.write( "\n" ); document.write( "Write the answer as a whole number.
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Algebra.Com's Answer #429991 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
For now, let \"+p+\" = the purchase price
\n" ); document.write( "The value is:
\n" ); document.write( "1st yr: \"+p+\"
\n" ); document.write( "2nd yr: \"+.7p+\"
\n" ); document.write( "3rd yr: \"+.7%2A%28+.7p+%29+\"
\n" ); document.write( "4th yr: \"+.7%5E3%2Ap+\"
\n" ); document.write( "etc
\n" ); document.write( "Let \"+V+\" = the current value of the laptop
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\n" ); document.write( "If \"+n+\" the number of years,
\n" ); document.write( "\"+V+=+.7%5E%28n+-+1%29%2Ap+\"
\n" ); document.write( "( I use the \"+n-1+\" because it makes the
\n" ); document.write( "1st year \"+.7%5E%28+1-1%29%2Ap+=+p+\" )
\n" ); document.write( "\"+p+=+1200+\"
\n" ); document.write( "\"+V+=+300+\"
\n" ); document.write( "\"+300+=+.7%5E%28+n-1+%29%2A1200+\"
\n" ); document.write( "\"+.7%5E%28+n-1+%29+=+1%2F4+\"
\n" ); document.write( "\"+.7%5E%28+n-1+%29+=+.25+\"
\n" ); document.write( "Take the log base 10 of both sides
\n" ); document.write( "\"+log%28+.7%5E%28+n-1+%29+%29+=+log%28+.25+%29+\"
\n" ); document.write( "\"+%28+n-1+%29%2Alog%28+.7+%29+=+log%28+.25+%29+\"
\n" ); document.write( "\"+n-1+=+log%28+.25+%29+%2F+log%28+.7+%29+\"
\n" ); document.write( "\"+n+=++log%28+.25+%29+%2F+log%28+.7+%29+%2B+1+\"
\n" ); document.write( "\"+n+=+%28+-.60206+%29+%2F+%28+-.1549+%29+%2B+1+\"
\n" ); document.write( "\"+n+=+3.8868+%2B+1+\"
\n" ); document.write( "\"+n+=+4.8868+\"
\n" ); document.write( "After the 4th year, the laptop will be
\n" ); document.write( "worth $300 or less.
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\n" ); document.write( "Check answer:
\n" ); document.write( "\"+V+=+.7%5E%28+n-1+%29%2A1200+\"
\n" ); document.write( "\"+V+=+.7%5E%284.8868-1%29%2A1200+\"
\n" ); document.write( "\"+V+=+.7%5E3.8868%2A1200+\"
\n" ); document.write( "\"+V+=+.24999%2A1200+\"
\n" ); document.write( "\"+V+=+300+\"
\n" ); document.write( "OK
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