document.write( "Question 62269: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( "

Algebra.Com's Answer #42999 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?
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\n" ); document.write( "Let x = time required when they all work together
\n" ); document.write( "Let the completed job (20 drinks) = 1
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\n" ); document.write( " $\"x%2F5+%2B+x%2F10+%2B+x%2F15+=+1\"$
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\n" ); document.write( "Mult eq by 30 to get rid of the denominator, resulting in:
\n" ); document.write( "6x + 3x + 2x = 30
\n" ); document.write( "11x = 30
\n" ); document.write( "x = 30/11
\n" ); document.write( "x = 2.73 min or 2 min 43.6 seconds
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