document.write( "Question 697390: 2-3i/1+i \n" ); document.write( "

Algebra.Com's Answer #429960 by KMST(5328) $\"\"$ $\"About$

You can put this solution on YOUR website!
I bet you meant (2-3i)/(1+i) = $\"%282-3i%29%2F%281%2Bi%29\"$
\n" ); document.write( " $\"1-i\"$ is the conjugate of $\"1%2Bi\"$
\n" ); document.write( "When you multiply conjugate complex numbers, you get a real number.
\n" ); document.write( " $\"%281%2Bi%29%281-i%29=1%5E2-i%5E2=1-%28-1%29-2\"$
\n" ); document.write( "That is very useful when trying to get rid of complex denominators.
\n" ); document.write( "You just multiply numerator and denominator times the conjugate of the denominator:
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\n" ); document.write( "NOTE:
\n" ); document.write( "2-3i/1+i = $\"2-3i%2F1%2Bi=2-3i%2Bi=2-2i\"$ is a different (easier) problem.
\n" ); document.write( "If want to write $\"%282-3i%29%2F%281%2Bi%29\"$ ,
\n" ); document.write( "and you are not able to draw a long horizontal line with $\"2-3i\"$ above it and $\"1%2Bi\"$ below it,
\n" ); document.write( "you must write out the brackets around $\"2-3i\"$ and around $\"1%2Bi\"$ that the long horizontal fraction bar implies. \n" ); document.write( "

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