document.write( "Question 60947This question is from textbook college algebra
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\n" ); document.write( "\n" ); document.write( "Jane went on a trip for a week. To rent a car she called two firms. Bob's wanted $35 per day with no mileage fee. The Rent-A-Car wanted $150 per week (7 days) but also wanted $.19 per mile. How many miles would have to be driven before the Rent-A-Car price is more than Bob's price? \r
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Algebra.Com's Answer #42996 by 303795(602)\"\" \"About 
You can put this solution on YOUR website!
Bob's Car rental charges $35 per day. This means that she would pay 7 times $35 = $245 for a week's car hire.\r
\n" ); document.write( "\n" ); document.write( "Rent-A-Car charges $150 per week which is $95 less than Bobs Car rental.
\n" ); document.write( "How far can you travel at 19 cents per mile if you have $95 to spend? Divide $95 by 0.19 to get 500. If Jane travels more than 500 miles then the Rent-A-Car price will be more than Bob's.
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