document.write( "Question 697366:
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document.write( "The product of two numbers is 1400. If three is subtracted from each number, their product becomes 1175. Find the bigger number. \n" );
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Algebra.Com's Answer #429943 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! XY=1400 \n" ); document.write( "X=1400/Y \n" ); document.write( "(X-3)(Y-3)=1175 \n" ); document.write( "XY-3Y-3X+9=1175 \n" ); document.write( "1400-3Y=3(1400/Y)=1175-9 \n" ); document.write( "1400-3Y=4200/Y=1166 \n" ); document.write( "-3Y-4200/Y=1166-1400 \n" ); document.write( "(-3Y*Y-4200)/Y=-234 \n" ); document.write( "-3Y^2-4200=-234Y \n" ); document.write( "-3Y^2+234Y-4200=0 \n" ); document.write( "3Y^2-234Y+4200=0 \n" ); document.write( "3(Y^2-78Y+1400=0 \n" ); document.write( "3(Y-50)(Y-28)=1400 \n" ); document.write( "Y-50=0 \n" ); document.write( "Y=50 ANS. THEN X*50=1400 OR X=1400/50 OR X=28 ANS. \n" ); document.write( "Y-28=0 \n" ); document.write( "Y=28 ANS. THEN X*28=1400 OR X=1400/28 OR X=50 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "50*28=1400 \n" ); document.write( "1400=1400 \n" ); document.write( "(28-3)(50-3)=1175 \n" ); document.write( "25*47=1175 \n" ); document.write( "1175=1175 \n" ); document.write( " |