document.write( "Question 697366:
\n" ); document.write( "The product of two numbers is 1400. If three is subtracted from each number, their product becomes 1175. Find the bigger number.
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Algebra.Com's Answer #429943 by checkley79(3341)\"\" \"About 
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XY=1400
\n" ); document.write( "X=1400/Y
\n" ); document.write( "(X-3)(Y-3)=1175
\n" ); document.write( "XY-3Y-3X+9=1175
\n" ); document.write( "1400-3Y=3(1400/Y)=1175-9
\n" ); document.write( "1400-3Y=4200/Y=1166
\n" ); document.write( "-3Y-4200/Y=1166-1400
\n" ); document.write( "(-3Y*Y-4200)/Y=-234
\n" ); document.write( "-3Y^2-4200=-234Y
\n" ); document.write( "-3Y^2+234Y-4200=0
\n" ); document.write( "3Y^2-234Y+4200=0
\n" ); document.write( "3(Y^2-78Y+1400=0
\n" ); document.write( "3(Y-50)(Y-28)=1400
\n" ); document.write( "Y-50=0
\n" ); document.write( "Y=50 ANS. THEN X*50=1400 OR X=1400/50 OR X=28 ANS.
\n" ); document.write( "Y-28=0
\n" ); document.write( "Y=28 ANS. THEN X*28=1400 OR X=1400/28 OR X=50 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "50*28=1400
\n" ); document.write( "1400=1400
\n" ); document.write( "(28-3)(50-3)=1175
\n" ); document.write( "25*47=1175
\n" ); document.write( "1175=1175
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