document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=697350>Question 697350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Work crews A, B and C can set up the steel structure of a building in 10 days if they work together. If they work alone, crew A would take 60 days to do the job and crew B would take 3 times long as long as crew C to do the job. How long would it take crews B, and C if each worked alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #429911 by </B><A HREF=/tutors/aboutme.mpl?userid=god2012><B>god2012(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=god2012><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=god2012><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=429911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution :\r<BR>\n" );
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document.write( "Total time taken by all 3 crews to complete work = 10 days<BR>\n" );
document.write( "Total work done by all 3 crews in 1 day = 1/10 <BR>\n" );
document.write( "Total time taken by crew A alone to complete work = 60 days<BR>\n" );
document.write( "Total work done by  crew A in 1 day = 1/60 <BR>\n" );
document.write( "therefore, total work done by B and C together in 1 day = 1/10 - 1/60 = 1/12<BR>\n" );
document.write( "But B = 3C<BR>\n" );
document.write( "B + C = 12<BR>\n" );
document.write( "4c = 12<BR>\n" );
document.write( "c = 3 days<BR>\n" );
document.write( "B = 9 days\r<BR>\n" );
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document.write( " </SPAN>\n" );
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