document.write( "Question 697335: Solve for x
\n" ); document.write( "5+ log x = log x^6
\n" ); document.write( "any help you can give would be greatly appreciated \n" ); document.write( "

Algebra.Com's Answer #429903 by Positive_EV(69) $\"\"$ $\"About$

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$\"log%28x%5Ea%29+=+a%2Alog%28x%29\"$ , so $\"log%28x%5E6%29+=+6%2Alog%28x%29\"$ .\r
\n" ); document.write( "\n" ); document.write( " $\"5+%2B+log%28x%29+=+6%2Alog%28x%29\"$ , subtract log(x) from both sides:
\n" ); document.write( " $\"5+=+5%2Alog%28x%29\"$ , divide both sides by 5:
\n" ); document.write( " $\"1+=+log%28x%29\"$ . Since log with no base given usually denotes log base 10, you want the value of x for which:\r
\n" ); document.write( "\n" ); document.write( " $\"10%5E1+=+x\"$ , so x = 10. \n" ); document.write( "

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